How to solve a first order ode

Consider a first-order ODE in the slightly different form p(x,y)dx+q(x,y)dy=0. (1) Such an equation is said to be exact if (partialp)/(partialy)=(partialq)/(partialx). (2) This

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Solution of First Order Linear Differential Equations

Given equation is x ′ − 4 x 2 + 16 = 0 ⇒ 1 x 2 − 4 x ′ = 4 So it is the first-order ODE of the form N ( x) x ′ = M ( t) where N ( x) = 1 x 2 − 4 and M ( t) = 4 I hope you know how to solve