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lim x→∞ x √x(16x+1)+ 4x lim x → ∞ x x ( 16 x + 1) + 4 x. Divide the numerator and denominator by the highest power of x x in the denominator, which is x = √x2 x = x 2. lim x→∞ x x √ x(16x+1) x2
Calculus. Evaluate the Limit limit as x approaches infinity of square root of x^6-5x^3-x^3. lim x→∞ √x6 − 5x3 − x3 lim x → ∞ x 6 - 5 x 3 - x 3. Multiply to rationalize the numerator. lim x→∞ (√x6
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