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How to find the x intercepts of a parabola

Are you trying to learn How to find the x intercepts of a parabola? If so, you have come to the right place.

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x intercepts of parabolas

intercepts\:(y-2)=3(x-5)^2; intercepts\:3x^2+2x+5y-6=0; intercepts\:(y-3)^2=8(x-5) intercepts\:(x+3)^2=-20(y-1)

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Parabola Intercepts

Since the equation for a parabola describe a quadratic function y=ax^2+bx+c, where a, b, and c are any real numbers such that a ne 0, we can find the x-intercepts by solving
x

Graphing Quadratics: The Leading Coefficient & The Vertex

!If the parabola only has 1 x-intercept (see middle of picture below), then the parabola is said to be tangent to the x-axis. How to find the x-intercepts Simply solve the quadratic equation by any