Are you trying to learn How to find the x intercepts of a parabola? If so, you have come to the right place.
intercepts\:(y-2)=3(x-5)^2; intercepts\:3x^2+2x+5y-6=0; intercepts\:(y-3)^2=8(x-5) intercepts\:(x+3)^2=-20(y-1)
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!If the parabola only has 1 x-intercept (see middle of picture below), then the parabola is said to be tangent to the x-axis. How to find the x-intercepts Simply solve the quadratic equation by any
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