log(3x4y−7) log. . ( 3 x 4 y − 7) Solution. ln(x√y2 +z2) ln. . ( x y 2 + z 2) Solution. log4( x −4 y2 5√z) log 4 ( x − 4 y 2 z 5) Solution. Combine each of the following into a single

Solve NowpH = −log [H+] = −log [0.0003] = 3.52287874528 This value is less than 7, so the apple juice is acidic. b) In the case of the ammonia, the hydrogen ion concentration is [H+] = 1.3 × 10−9, so:

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75 =16807 7 5 = 16807 Solution. 163 4 = 8 16 3 4 = 8 Solution. (1 3)−2 = 9 ( 1 3) − 2 = 9 Solution. For problems 4 – 6 write the expression in exponential form. log232 = 5 log 2 32

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6. Solve for x if log(x-1)+log(x+1)=log 2 1. Solution: log(x-1)+log(x+1)=log 2 1. log(x-1)+log(x+1)=0. log[(x-1)(x+1)]=0. Since, log 1 = 0 (x-1)(x+1) = 1. x 2-1=1. x 2 =2. x=± √2.

Practice: Evaluate logarithms (advanced) Relationship between exponentials & logarithms. Relationship between exponentials & logarithms: graphs. Relationship between exponentials &

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log2(x +1)−log2(2−x) = 3 log 2 ( x + 1) − log 2 ( 2 − x) = 3 Solution. log4(−x) +log4(6 −x) = 2 log 4 ( − x) + log 4 ( 6 − x) = 2 Solution. log(x) =2 −log(x−21) log. . ( x) = 2 − log. .

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